MatPlus.Net

 Website founded by
Milan Velimirović
in 2006

23:36 UTC
ISC 2025
 
  Forum*
 
 
 
 

Username:

Password:

Remember me

 
Forgot your
password?
Click here!
SIGN IN
to create your account if you don't already have one.
CHESS
SOLVING

Tournaments
Rating lists
1-Jul-2025

B P C F





 
 
MatPlus.Net Forum General Gratuitous Fairy Conditions against duals :-)
 
You can only view this page!
(1) Posted by Hauke Reddmann [Sunday, Apr 20, 2025 20:40]

Gratuitous Fairy Conditions against duals :-)


Game starting position. h#2, Koeko
Since White technically has the move, either mate White or start with Black.
Only 1.f6 e3 2.g5 Dh5# remains :-)
 
(Read Only)pid=26788
(2) Posted by Peter Wong [Monday, Apr 21, 2025 08:40]

That's really funny!

For a second I thought Monochrome would work too, but alas a single dual remains.
 
(Read Only)pid=26789
(3) Posted by seetharaman kalyan [Tuesday, Apr 22, 2025 19:31]

Koeko+Patrol
e6 f3 Be7 g5 Bh4#
 
 
(Read Only)pid=26793
(4) Posted by Joost de Heer [Tuesday, Apr 22, 2025 22:14]

?? Bh4 isn't mate, g5 defends against the check (assuming you meant 'g4' where you wrote 'g5')
 
   
(Read Only)pid=26794
(5) Posted by seetharaman kalyan [Wednesday, Apr 23, 2025 13:14]

Oh... 😭 Omitted to check
 
   
(Read Only)pid=26796
(6) Posted by Jacques Rotenberg [Friday, Apr 25, 2025 08:18]

Transparent pieces : mate in 1!

1.Bb5#!
1.Rxa8+? Q(or R)xa8! 1.Rxh8+? Q(or R)xh8!
1.Qh5? Rxh5!
 
   
(Read Only)pid=26801
(7) Posted by Hauke Reddmann [Friday, Apr 25, 2025 09:22]

@Jacques: 👍 Lulz were had, alas, I doubt this condition replaces Chess960
in OTB tournaments soon - since apparently Popeye doesn't have it :-)
 
   
(Read Only)pid=26802
(8) Posted by Jacques Rotenberg [Tuesday, Apr 29, 2025 19:28]

Helpmate to the white king in 4
AntiNeuKöko
The 1st move being 1.a4

1.a4 e5 2.h4 Q×h4 3.ç4 Q×f2 4.Rh4 Q×h4‡
 
   
(Read Only)pid=26813
(9) Posted by Jacques Rotenberg [Wednesday, Apr 30, 2025 12:20]

Helpmate to the white king in 4
AntiNeuKöko
white maximum
Transmuted kings

1.d4 h5 2.Bf4 a5 3.B×ç7 f5 4.B×a5 Q×a5‡
 
   
(Read Only)pid=26815
(10) Posted by udo [Tuesday, May 6, 2025 11:30]

Alphabetiques
Back-to-Back
h#8
1.a5 a4 2.Ra6 Ra3 3.Rb6 Ré3 4.R×b2 Sa3 5.Rb1 Sb5 6.R×ç1 Sd6+ 7.ç×d6 ç×ç8=S 8.b6 S×d6‡
 
   
(Read Only)pid=26838
(11) Posted by seetharaman kalyan [Tuesday, May 6, 2025 15:30]

@Udo
This is a great find. I would have been happy to take for The Problemist.
 
   
(Read Only)pid=26839
(12) Posted by udo [Thursday, May 8, 2025 13:41]

@seetharaman kalyan
yes
 
   
(Read Only)pid=26843
(13) Posted by Hauke Reddmann [Friday, May 9, 2025 10:58]

A few "near misses":

PAS, AlphabeticChess, HaanerChess, ser-#12
1.a2-a4 2.a4-a5 3.a5-a6 4.a6*b7 5.Sb1-c3 6.b2-b4 7.b4-b5 8.b5-b6 9.b6*c7 10.b7*c8=Q 11.Sc3-e4 12.c7*d8=Q #
You can add "no underpromotions" (two R work) but still 11.Sc3-d5 is the same.

PAS, Volage, BlackMaximummer, ser-h#11
1.Sb8-c6=w 2.Sg8-h6=w 3.a7-a5 4.Ra8-a6 5.Ra6*c6 6.Rc6*h6=w 7.c7-c5 8.Qd8-b6 9.Qb6*h6 10.Qh6-a6=w 11.b7-b5 Qa6*c8 #
The first two moves may be swapped.

PAS, EinsteinChess, WhiteMaximummer, h#4
1.e7-e5 Sg1-h3=P 2.Bf8-a3=S Sb1*a3=B 3.c7-c5 Ba3*c5=R 4.Qd8-e7=R Rc5*c8=Q #
1...Sf3=P is the same.

PAS, AlphabeticChess, EinsteinChess, ser-#17
1.a2-a4 2.Ra1-a2=B 3.Ba2-e6=S 4.a4-a5 5.a5-a6 6.a6*b7=S 7.Sb1-c3=P 8.b2-b4 9.b4-b5 10.b5-b6 11.b6*a7=S 12.Sa7-c6=P 13.Sb7*d8=B 14.Bc1-a3=S 15.Sa3-b5=P 16.b5-b6 17.b6*c7=S #
12. Sa7-c8=B also works. Bummer.

Possibly in one of the next SCHWALBE I've got a hit, though (and the fairy "clerk" added a twin even more hair-raising :-)
 
 
(Read Only)pid=26848

No more posts


MatPlus.Net Forum General Gratuitous Fairy Conditions against duals :-)