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(441) Posted by Arno Tungler [Tuesday, Oct 24, 2023 08:44] 
I agree with Seetharaman — who would have thought that this turns out to be so attractive…
Anyhow, here is an improved version of my above try, are the additional cookstoppers sufficient??
Miodrag Mladenovic and AT
(= 11+16 )
serhs=19 C?
Solution: 1.cxd6 2.Sxa6 3.Sxc5 4.a5 5.a4 6.a3 7.Ra4 8.Qa5 9.Kd8 10.Kc7 11.Kb6 12.Kb5 13.Kxb4 14.b5 15.Sxe4 16.Sxg3 17.Sxe2 18.Sxc1 19.Sxb3 & 1.c3+ Kxc3=
EDIT. Still cooked by I.e. 1.cxd6 2.dxc5 3.cxb4 4.e5 5.h5 6.h4 7.hxg3 8.Rh4 9.Rxe4 10.Rc4 11.Rxc2 12.Rxc1 13.Ke7 14.bxa6 15.Kf6 16.Kf5 17.f6 & 1.e4+ K~=
This needs more thought… 

(442) Posted by James Malcom [Wednesday, Oct 25, 2023 03:03] 
This may help inspire.
serhs=17 Schema
(= 10+16 )
1. cxd6 2. Qxb6 3. Qxg1 8. bxa1=Q 9. Qxa6 10. Qd3 15. a1=Q 16. Qe5 17. Ra1 & 1. h4 h5 

(443) Posted by Olaf Jenkner [Wednesday, Oct 25, 2023 19:05] 
The move h3h4 doesn't force a selfstalemate.
A queen on h3 could play Qh3xd7+ Kxd7=
Another question:
Is wPa4 in Serhs=16 (197) necessary? The solution works without it
and I see no other way for the rook walk. 

(444) Posted by Joost de Heer [Thursday, Oct 26, 2023 10:18] 
Instead of Qe5 Ra1, black can also play Ra5 Re5, or a1=S Sc2 Ra1. And the latter cook means that perhaps moving Olaf's queen to e2 may fix this.
(= 10+16 )
1. cxd6 2. Qxb6 3. Qxg1 8. bxa1=Q 9. Qxa6 10. Qd3 15. a1=S 16. Sxc2 17. Ra1 & 1. Qxe7 K/B/Sxe7= 

(445) Posted by Arno Tungler [Thursday, Oct 26, 2023 16:31] 
This is cooked i.e. by 1.cxd6 2.Qxb6 4.Qd3 9.bxa1=B 11.Bxc1 12.Bxd2 13.h5 16.Rxg1 & 1.Qxe7+
And with an additional wPc2 also 1.cxd6 2.Qxb6 4.Qd3 9.bxa1=R 10.Sc6 12.Sxc2 13.h5 16.Rxg1 & 1.Qxe7+ 

(446) Posted by James Malcom [Saturday, Oct 28, 2023 04:35] 
More trying is the only way forward.
serhs=18 Schema
(= 11+16 )
1. cxd6 2. Qxb6 3. Qxb4 4. b5 5. bxa4 8. a1=Q 9. Qaxa5 10. Qxg5 15. a1=Q 16. Qb2 17. Ra1 18. Ba6 & 1. Qxd7 K/N= 

(447) Posted by Georgy Evseev [Saturday, Oct 28, 2023 10:22] 
@446
Cooked
1.cdQb6Qxb4Qxa45.Qxa5Qxg5Qg1a5a410.a3a2a1RRa3Rxc315.Rxe316.Ra2 & Qxd7+ 

(448) Posted by Olaf Jenkner [Wednesday, Jan 31, 2024 22:14] 
Posted by Алексей Гаспарян
I offer a new position.
(= 9+16 )
Serhs#14
Solution: 1.cd 2.ab 3.ba 4.a4 5.ab 6.Ra4 7.Qa5 8.Kd8 9.Kc7 10.Kc6 11.Kd5 12.Ke4 13.Kf3 14.Re4 Ne1+ 15.Q(R)*e1X.
Dear chess friends!
Do you think this could work? 

(449) Posted by Olaf Jenkner [Wednesday, Jan 31, 2024 22:59] 
Cooked in 13 moves:
1. exd6 2. d5 3. c5 4. c4 5. cxd3 6. g6 7. gxf5 8. Qf6 9. Ba3 10. Kf8 11. Kg7 12. Bc1 13. Qa1 Be7+ Bg5# 

(450) Posted by Алексей Гаспарян [Thursday, Feb 8, 2024 15:46] 
I suggest adding a white pawn g4. 

(451) Posted by Olaf Jenkner [Thursday, Feb 8, 2024 23:57] 
Cooked in 13 moves:
1. exd6 2. c5 3. c4 4. cxd3 5. Qxg5 6. Ke7 7. Kf6 8. Ke5 9. Kd4 10. Kc3 11. Qe3 12. d5 13. d4  Rc2+ dxc2# 

(452) Posted by Алексей Гаспарян [Friday, Feb 9, 2024 18:56] 
Olaf,most likely,this scheme does not allow to do it in 14 moves,but it might be possible to do it at least in 13, if you force 1.cd
I would like to know this in this position:
W: Kd1,Re6,Rg2,Bg5,Nd3,Nd6,pp.b3,e5,g4 (9) B: homebase (16) Ser.hs#13 C?
Thank you! 

(453) Posted by Arno Tungler [Saturday, Feb 10, 2024 02:20] 
1.cxd6 2.Qa5 3.Qxe5 4.Qxg5 5.Qe5 6.Qc3 7.Kd8 8.Kc7 9.Kc6 10.Kd5 11.Kd4 12.Kxd3 & Rd2+ Qxd2# 

(454) Posted by Алексей Гаспарян [Sunday, Feb 11, 2024 15:31] 
Thank you,Arno!When you're working on a plan,it's hard to find a cook. I modified the diagram a little.Now to get to f3 the king needs to destroy the c6 bishop. Can this help you survive? Please also look at this attempts of mine.
W: Kd1,Rb6,Bc6,Bg3,Nd3,Nd6,pp.a5,b3,e6,f2,h3 (11) B: homebase (16) Ser.hs#14 C?
or without rook b6 and pawn a5  Ser.hs#13 C? 

(455) Posted by Arno Tungler [Monday, Feb 12, 2024 01:26] 
1.exd6 2.dxc6 3.Ke7 4.Kxe6 5.Kd5 6.Ke4 7.Kf3 8.Qf6 9.Qc3 10.Bf5 11.Be4 12.d5 13.Bb4 & Se1+ Qxe1# 

(456) Posted by Алексей Гаспарян [Tuesday, Feb 13, 2024 15:32] 
How not to let the black king go along a different route  apparently this requires even deeper thought.
Maybe someone ready to help?
Arno, by the way, I recently tried to correct your ser.h=19 (see posts 397,403)
W:Kf2,Qb5,Re2,Bh2,Bh5,Ne1,Ne3,pp.b6,c4,e6,f5,g3,h6 (13)
B:homebase (16) Ser.h=19 with solution : 1.ab 2.Ra4 3.R*c4 4.Rc6 5.d5 6.d4 7.d3 8.de 9.Qd2 10.Nd7 11.Rc3 12.R*e3 13.R*g3 14.Q*h6 15.Qg6 16.h6 17.Qh7 18.Rg6 19.f6 B*c7=.
Could this work? 

(457) Posted by Hauke Reddmann [Tuesday, Feb 13, 2024 22:23] 
OK, who else is yearning for an AI which not only finds cooks, but
tries edits to fix them? :) 

(458) Posted by Arno Tungler [Wednesday, Feb 14, 2024 01:49] 
Please see post 433. I reduced already to 18 moves. 

(459) Posted by Michel Caillaud [Friday, Feb 16, 2024 10:16] 
With not so many attempts, new records should be possible in the serhs field.
Should not (197) be Tüngler/Mladenovic in view of (195)?
(= 8+16 ) serhs#16 C? 

(460) Posted by Arno Tungler [Sunday, Feb 18, 2024 02:36] 
There were quite some attempts 200 posts ago...
I fully agree with the [197]  it is MM & AT but I am also 100 % sure that this is not the last word...
For Michel's serhs#16 it would be good to have the solution. 

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