﻿﻿ MatPlus.Net

Website founded by
Milan Velimirović
in 2006

23:52 UTC
 ISC 2021

Remember me

 CHESS SOLVINGTournamentsRating lists1-Apr-2021

MatPlus.Net Forum Helpmates An easy h#2

### An easy h#2

This problem was rejected by The Problemist & The Problemist Supplement, reasons included being too easily solved. I had hoped that the twinning might be slightly unusual....

(= 6+9 )

H#2

(b)

(= 9+6 )

H#2

I think the Solution is.1.Bc1 Bxc1 2.Qd2 Bb2#. White bishop is unnecessary for this mate and idle. The solution for the twin is definitely simple with queen mate on base rank and has no strategy.

This twinning type is known as Polish type. Definition from Encyclopedia of Chess Problems by Velimirovic&Valtonen (2012):
Polish type: twin that is created by changing the colors of all the pieces on the board. It is desirable to attain maximal economy of all pieces (even including Pawns) in mates which would be then - ideal mates, but this is not an explicit thematic requirement. Example:

TURA, Waldemar
I.pr Wola Gulowska 1988 / TT
(= 3+3 )
h#3 b) PolishType
B1b5/8/3k4/3P4/1b2K3/8/8/8

a)
1.Kd7 d6 2.Ba5 Kd5 3.Bd8 Bc6# (IM)
b)
1.d4 Ke7 2.Ke5 Be6 3.Be4 Bd6# (IM)

The first diagram should be as posted plus :- remove Bb7, add Pa6

Accordingly in (b) remove bb7, add pa6

Apologies, this slightly more economical version is from a suggestion by Michael Mcdowell when I first composed this.

Still you persisted with the idle Bb7 version?

For some reason the diagram which I had on file hadn't been updated with the improved economy, but I remembered when the comment about redundant Bb7 was made. The problem is from some years ago.

(7) Posted by Siegfried Hornecker [Wednesday, Apr 28, 2021 16:00]

EDIT: Ok, b is correct. I see now.

So the solutions are (mark to see):

a) 1.Bc1 Bxc1 2.Qd2 Bb2 mate
b) 1.Bxf4 Qh3 2.Kc1 Qf1 mate

Yes, indeed fast and easy to solve.