|(1) Posted by Hauke Reddmann [Friday, Aug 25, 2017 13:02]; edited by Hauke Reddmann [17-08-25]|
Pas de deux
Inspired by a MP posting ("Mirror Moves"), I quickly composed the
following 2#. (It's substandard but I only wanted to show the theme.)
(= 7+3 )
Only the thema variants (go find everything else alone, including solution :-) :
1.Sa8? Sa4!, 1.Se8? Se4!, 1.Sa6? Sxa6!, 1.Se6? Sxe6!
I also composed a lot of examples with parallel moving on the occasion
of Loshinsky's 100th, and will make a little article (maybe for his
111th? :-). I feel that this problem could be thrown in for good measure,
and obviously a third possibility (i.e. white and black pieces move in
the opposite direction) is still unresearched. Also note that in this
problem Black mimics White, while in the Loshinsky-inspired ones it's
the other way round.
So: Whoever wants to jump in here, will be included in the article.
Only thematic requirement:
1a Whites mate mimics Blacks defense or
1b Blacks parry mimics Whites try, and "mimic" is
2a Same vector or
2b Mirrored vector or
2c 180° Rotated vector
(or 2d free rotated vector, if your muse is a troll :-)
(This problem: 1b2b.)
Show *at least* 2 variants lest the solver will probably find it
EDIT: In the article, only orthodox 2#. What you add here is
up to your fancy ;-)
|(2) Posted by Hauke Reddmann [Saturday, Aug 26, 2017 13:29]|
Have another one, composed on the fly during the (club) Lübeck
solving competition (you know me, I'm read in half the time :-)
(= 7+7 )
1.Sf6! (2.Th7) Be5/Be3 2.Bg3/Bg5
|(3) Posted by Hauke Reddmann [Monday, Aug 28, 2017 22:36]|
I don't know what keeps you from adding, I compose an example
in five minutes (it has to be just an example after all,
I don't want to take away a Loshinsky-like masterpiece from you :-)
(= 8+7 )
1.f8Q (Fleck) Qc3/Qc4/Qc5 2.Qf6/Qf5/Qf4
1a2c, illustrating mainly what you should NOT do, under any circumstances:
let concurrent parades like Qxb2 or Bc3 interfere with the solver
recognizing the intended theme.
|(4) Posted by Michael McDowell [Tuesday, Aug 29, 2017 00:26]|
A related idea:
Op de Hoogte 1913
(= 11+8 )
Mate in 2
|(5) Posted by Hauke Reddmann [Tuesday, Aug 29, 2017 10:45]; edited by Hauke Reddmann [17-08-29]|
Neato. Falls under my description (EDIT: 1a2d, 90°) and will definitely be
included. (I personally avoid unrelated byplay and would
move everything "against the wall" to save a few pieces [8+8],
but that is stuff for endless discussion :-)
|(6) Posted by Daniel Wirajaya [Tuesday, Sep 26, 2017 15:40]|
Here is a simple one with three different motivations.
(= 5+3 )
Key: 1. Kxd7 [2. Bxh7#]
1... Bg6 2. Bf7#
1... Bf5+ 2. Be6#
1... Be4 2. Bd5#
(1... Bxg8 2. Rxg8)
|(7) Posted by seetharaman kalyan [Tuesday, Sep 26, 2017 20:14]|
I suppose that another variation can be easily added with a different (but inferior key
|(8) Posted by Arpad Rusz [Tuesday, Sep 26, 2017 22:25]|
A task featuring the theme 7 times using queens:
|(9) Posted by Michael McDowell [Tuesday, Sep 26, 2017 22:26]|
Four thematic variations in a nice mutate by Ahues, though with only two motivations.
5th Prize, Chess 1956
(= 7+8 )
Mate in 2
Set 1...B~ 2.Rxg6
|(10) Posted by Darko Šaljić [Wednesday, Sep 27, 2017 09:30]|
2 Pr Probleemblad 1964
(= 10+11 )
|(11) Posted by Hauke Reddmann [Wednesday, Sep 27, 2017 14:20]|
THX for the additions. Obviously, there
is a ton of rook-rook-duels in the n# genre, and
"duel" in the 2# Albrecht database alone lists 580 entries.
Still much research to do :-) Random example:
(= 12+11 )
S. Shedej, Sportivna Gaseta 1990
@Arpad: I can't count the Bakcsi problem,
since the vectors are not always equal
(otherwise any "duel" would qualify).
@Darko: This seems to be a slightly economized
version with respect to the one in the Albrecht database.
@Seetharaman and Daniel: Indeed.
(= 6+5 )
Since the Ahues one is far superior, just added
to answer the question (yes, 3 motivations work).
|(12) Posted by Hauke Reddmann [Friday, Oct 13, 2017 16:05]|
Heres one for 1b2a by Klemanic: http://www.yacpdb.org/#244143
I tried my best to make it four RR oppositions (I had to slap
a sucking solution on it in return), but the matrix is fighting back.
Can you do it better?
(= 8+10 )
1.Rb4/c4/e4/f4? Rb3/c3/e3/f3! (1.Qa6!)
|(13) Posted by seetharaman kalyan [Friday, Oct 13, 2017 21:01]|
If you forgo the flight giving key and have a key like 1.Kb6 threat 2.Qc7 you get an almost dual free version.
|(14) Posted by Jacques Rotenberg [Friday, Oct 20, 2017 00:40]|
With only 3 tries but with black and white correction :
(= 8+5 )
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