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(1) Posted by Abdelaziz Onkoud [Wednesday, Jan 16, 2019 22:09]; edited by Abdelaziz Onkoud [19-01-16] |
Models mats Do you know of any other examples of h#2 (no twin) that cumulates many models mats? Beyond 8 solutions...
A.Onkoud , StrateGems 2005 , 1° MH (v)
(= 3+12 )
h#2, 8 solutions
(repeated moves Kf5 and c3)
A.Onkoud , The Problemist 2018
(= 11+8 )
h#2 , 8 solutions
(No repeated moves ) |
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(2) Posted by Viktoras Paliulionis [Thursday, Jan 17, 2019 11:10]; edited by Viktoras Paliulionis [19-01-17] |
Ingemar LIND
200 TT, SuperProblem, 2017-18
Spec. Prize
(= 3+12 )
h#2 10 sol.
(No repeated moves) |
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(3) Posted by Branislav Djurašević [Thursday, Jan 17, 2019 11:11]; edited by Branislav Djurašević [19-01-17] |
I found all 8 solutions looking from diagram for almost 15 minutes. First one is: 1.Bg4 ba3 2.Bf3 B:c2# but I let others to find next seven solutions and enjoy during the solving so as I did! It is really entertainly. Problem is without technically flaws and black king movement. Well done Abdelaziz! |
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(4) Posted by Abdelaziz Onkoud [Thursday, Jan 17, 2019 11:20]; edited by Abdelaziz Onkoud [19-01-17] |
Now in 11 solutions !
(= 3+13 )
+ 1.ç5 R×ç5 2.Rç8 R×ç8‡
Rc5 (repeated move) |
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(5) Posted by Branislav Djurašević [Thursday, Jan 17, 2019 11:30]; edited by Branislav Djurašević [19-01-17] |
I prefer problem with non concurrent mates. So, A.Onkoud , The Problemist 2018 looks as perfect setting. |
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(6) Posted by Viktoras Paliulionis [Thursday, Jan 17, 2019 11:38] |
Possibly the author knew the position with 11 mates, but the theme was "without repetitions". |
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(7) Posted by seetharaman kalyan [Thursday, Jan 17, 2019 12:09] |
The 11th solution is an obvious and & simple addition. Author avoided it for the tourney which prohibited repetition |
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