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| (1) Posted by James Malcom [Saturday, Oct 12, 2019 04:45]; edited by James Malcom [19-10-12] |
The Black Home Task
Hehe. I love puns! A box of chocolates for everyone who can figure it out!
Anyhoo, I had an “idea,” after reseeing an old problem, to force as many Black pieces as possible back home in a selfmate.
Did I achieve four?
Yes, the key is bad, but you gotta live the checks, as otherwise this would be nearly impossible to achieve.
s#5, Cooked?
 (= 12+8 )
Solution:
1. bxc8=N+ Bxc8
Killing the guard of the 8th rank, Black’s light-squared bishop covers e6
2. g8=N+ Nxg8
Opening a line for the Black dark-squared bishop
3. f8=Q/B+ Bxf8
The Black dark-squared bishop guards d6
4. Qc5+ Ke8
Preparing the final check
5. Ba4+ Rb5#
Forced checkmate+selfpin
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| (2) Posted by Hauke Reddmann [Saturday, Oct 12, 2019 12:13] |
Do you know the 2005 Costeff humor study? White Home, but still.
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| (3) Posted by Michal Dragoun [Saturday, Oct 12, 2019 12:22] |
There is a (quite famous, I think) selfmate with home returns of all eight white officers by Mark Kirtley, PDB P1081510.
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| (4) Posted by James Malcom [Saturday, Oct 12, 2019 13:46] |
Yes, I know of both-Krabbe #288. A box of chocolate for you both!
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| (5) Posted by James Malcom [Saturday, Oct 12, 2019 17:58]; edited by James Malcom [19-10-12] |
The final, corrected version of my problem can be seen here: http://superproblem.ru/archive/probl/Sn/Malcom-s5-2019.gif
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| (6) Posted by James Malcom [Monday, Oct 14, 2019 19:55] |
Now the return of 5 Black pieces has been achieved: http://superproblem.ru/archive/probl/Sn/Malcom-s5-2019-2.gif
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| (7) Posted by seetharaman kalyan [Monday, Oct 14, 2019 21:04] |
Well done!
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| (8) Posted by James Malcom [Monday, Oct 14, 2019 22:03]; edited by James Malcom [19-10-14] |
Thanks seetharaman!
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| (9) Posted by Vitaly Medintsev [Tuesday, Oct 15, 2019 08:05] |
This record was just broken by Grigory Popov - http://superproblem.ru/archive/probl/Sn/Popov-s7-2019-2.gif
6 black pieces return to their initial positions!
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| (10) Posted by Frank Richter [Tuesday, Oct 15, 2019 11:38] |
This s#7 is an impressive construction, but we should note, that in final position the bQ has left again the original square.
Kirtley's white homebase task (that was taken as inspiration) shows all 8 white pieces in homebase position at the end.
This is of course more difficult, but should be the ultimate target for the black homebase task too.
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| (11) Posted by Miodrag Mladenović [Tuesday, Oct 15, 2019 12:26] |
In my opinion S#7 by Popov is incorrect problem. The 5th white move is not unique (5.b8Q/R+). This is the major dual if it's not on the lat move and I do not think it can be accepted. This cannot be counted as a task.
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| (12) Posted by James Malcom [Tuesday, Oct 15, 2019 13:58]; edited by James Malcom [19-10-15] |
Adding on to Frank’s words, Popov put his s#7 as a seprate record of 6 pieces going back during the game, while my s#5 is the record for the game ending with the pieces in place.
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| (13) Posted by Olaf Jenkner [Tuesday, Oct 15, 2019 17:07] |
Popov's stipulation should be: s#1 in 6 moves
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| (14) Posted by James Malcom [Tuesday, Oct 15, 2019 19:33] |
Miiodrag, in reagrds to your opinion, then you would also think that my s#5 is incorrect.
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| (15) Posted by Olaf Jenkner [Tuesday, Oct 15, 2019 21:40] |
See Article 13 of the codex:
https://www.wfcc.ch/1999-2012/codex/
I wonder why dualized problems should not be unsound. In my opinion a promotion dual can be tolerated if the promoted piece is immediately captured. The composer should avoid such promotions, but such problems are never cooked.
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| (16) Posted by Joost de Heer [Tuesday, Oct 15, 2019 22:15] |
13.2 needs major rewording, since the current wording renders compositions with multiple solutions branching after the first move (e.g. 2.2.1.1) as unsound.
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| (17) Posted by Olaf Jenkner [Tuesday, Oct 15, 2019 22:49] |
This article only means help-play problems.
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| (18) Posted by Miodrag Mladenović [Wednesday, Oct 16, 2019 15:52] |
Just to confirm. I do think that S#5 is incorrect too. I think that promotion dual can be only accepted on the last move. Although per codex it looks like this dual is only accepted in helpmates on the last move. This would mean that even if there is a dual on the last white move the problem is incorrect.
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| (19) Posted by Joost de Heer [Wednesday, Oct 16, 2019 16:18]; edited by Joost de Heer [19-10-16] |
QUOTE
This article only means help-play problems.
Yes, I know (although the footnote refers to other types of composition, e.g. direcctmates).
Let's take the various rules used in this article:
Article 10 – Dual
A dual is said to occur if, after the first move, there is more than one method of satisfying the stipulation.
Article 13 – Unsound Chess Compositions
(2) Help-play compositions are unsound also if they are dualized, except that in the final move a promotion into different pieces having partially the same power (for example queen/rook or queen/bishop) may be tolerated [16]
According to article 10, a helpmate with stipulation 2.2.1.1 is dualistic, since after the 1st move there are 2 methods (i.e. more than one) of satisfying the stipulation.
Accorting to 13.2, dualistic helpmates are unsound (unles[..], which is not relevant here), so a helpmate with 4 solutions, divided as 2.2.1.1 is unsound.
@Miodrag: Duals aren't mentioned in article 13 (which deals about unsoundness) for direct play, so dualistic directmates aren't unsound.
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| (20) Posted by Olaf Jenkner [Wednesday, Oct 16, 2019 17:57] |
... for direct play, so dualistic directmates aren't unsound.
Hard to believe, but written in the codex.
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