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MatPlus.Net Forum Threemovers Two different battery en passant mates

### Two different battery en passant mates

Aleksey Oganesjan
SuperProblem, 07-08-2020
(= 9+4 )

#3

1.Qg7? zz 1...b5 2.Qxb7 b4 3.Qxb4#, 1...bxc5!
1.Qg6? zz 1...b5 2.Qb6 b4 3.Qxb4#, 1...bxc5!
1.Qg5? zz 1...bxa5 2.Qe7 – 3.c6#, 2...b5 3.cxb6 e.p.#, 1...b5!
1.Qd2? – 2.Sb5+ Ka4 3.Qb4#, 1...bxa5 2.Qd6 – 3.c6#, 2...b5 3.cxb6 e.p.#, 1...bxc5!

1.Qg8! zz
1...bxc5 2.Qa8! b5/b6 3.axb6 e.p.#
1...bxa5 2.Qf8! – 3.c6#, 2...b5 3.cxb6 e.p.#
1...b5 2.cxb5! b6 3.Qb3#

To my surprise, I didn't find any anticipations for this simple but nice scheme with two battery (orthogonal and diagonal) e.p. mates!

Now I just found only a following distantly similar problem from another genre - #2:

Vasil Dyachuk, Valery Kopyl
7. ECSC Lowicz 2011 TT
1. ehrende Erwähnung
(= 10+6 )

#2*

*1...d5 2.exd6 e.p.# (A) / cxd6 e.p.# (B)
*1...Rb6+ 2.e6# (C) / cxb6# (D)

1.Bh6? - 2.Bd2#
1...d5 2.cxd6 e.p.# (B)
1...Rb6+ 2.cxb6# (D)
1...b1S!

1.Rh8! - 2.Rh3#
1...d5 2.exd6 e.p.# (A)
1...Rb6+ 2.e6# (C)

But here (compared to my #3):
1) two different White rear battery pieces;
2) both batteries are ready initially.

So this #2 and my #3 in a sense complement each other: in #3 batteries are created during solution and in #2 ready batteries are destroyed in try and in solution :)

A very nice idea executed masterfully! En passant checkmates are almost always "diluted," in a sense, of course, but so long as they are the best Black defense, they count.

Also, just as the opposite, it is entirely possbile for one battey to give two different en passant mates. Here's quickie that I threw together.

#2
(= 7+5 )

Here some cool problem that adds 2 black ep to the theme:

(= 9+11 )

Abdelaziz Onkoud
Sächsische Zeitung
22.9. 1995

If you want even more, Fröberg did 4 white ep,
although in phases.

(5) Posted by Kenan Velikhanov [Saturday, Aug 8, 2020 11:54]

6th FIDE World Cup
5th comm
Kenan Velikhanov
(= 11+8 )

1.Rb5? - 2.Sg6# (A)
1...c5 2.d:c6 e.p.#, 1...Q:c3 2.Q:e4#, 1...B:c3!
1.Qb5? - 2.Sg6# (A)
1...c5 2.Qb8# (d:c6 e.p.?), 1...B:f5 2.Sc6# (B), 1...Qg2!
1.Qh5? - 2.Sc6# (B)
1...g5 2.Qh8# (f:g6 e.p.?), 1...B:d5 2.Sg6# (A), 1...Q:c3!
1.Rh5! - 2.Sc6# (B)
1...g5 2.f:g6 e.p.#, 1...Q:c3/Qd2/Qc1 2.Q:e4#

four en passant, in try and in solution