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MatPlus.Net Forum General The Black Valladao in a single sequence

The Black Valladao in a single sequence

The other day I went looking for problems that feature a Black Valladao. I didn't want it in phases though, but in a single sequence. To my shock, there was nigh none. I only found two I knew of aleady-Popov's double Valladao problem (P1254435-http://superproblem.ru/archive/probl/N/Popov-11-2012.gif) and the lesser known double Valladao by Kostylev (P1377964-http://superproblem.ru/archive/probl/N/Kostylev-8x-2015.gif).

Thankfully, Andrew was able to find a third and only other one that luckily came in minimum form.
Valery Frigin, Die Schwalbe 1974, #4-P1287898
(= 8+10 )

The only flaw with this one is that there is a promotion dual. Andrew and I managed a Meredith with another matrix I found on chess.com.--https://www.chess.com/forum/view/more-puzzles/mate-in-5-a-black-triplet?page=1

JM and Andrew Buchanan, #4
(= 8+4 )

1. b4! axb3ep+ 2. Bxb3 e1=N+ 3. Kb1 0-0-0 4. Rc7#

The only setback here is that the castling isn't forced, although is made up for by the presence of only themetic Black units. It is a given that always one of three themeatic moves will never be fully forced, but the castling and a unique promotion should be IMO, leaving en passant as a Black defense on the last move.

Frigin's problem is nearly perfect in that sense-it just a non-dualed promotion, so I set out to make a problem using his ideas. After quite some work, I imperfectly managed it.

After Frigin, #4
(= 10+9 )

1. Qxh7 hxg1=N+ 2. Nxg1 O-O-O 3. d4 exd3 4. Bb7#

The forced castling and unique promotion (alwyas a knight) are present with an en passant defense as planned. If a decent key can be managed, the theme of a "perfect" Black Valladao in a full sequence will be done.

Who knows of more such problems?

Rewan, you should define "forced". "All other moves lead to a faster mate"?
As you can't force castling in the sense of *only* move, obviously.

That's exactly what I meant Hauke. "Forced" as in the only move, or else Black will be mated faster.

Anatoly Styopochkin
13706, Schweizerische Schachzeitung (jan. 93)
(= 8+9 )

6#
1.d4! [2.Qg6+,Qg8+,Qh8+,d5,c4] e×d3 e.p.+ 2.Kd2 f2 3.Bd6 [4.Qe7,Qg8,Qf8‡] 0-0-0 4.Qg2 [5.Qa8‡] f1=S+ 5.K×d3 [6.Qa8‡]

Anatoly Styopochkin
S. Sakharov Jubilee 50
4th HM
(= 7+12 )

7#
1.Qh2! [2.Q×h8+ Rg8 3.Q×g8‡] f1=S+ 2.Kc1 [3.Q×h8+,R×c7,Rd7] S×h2 3.c4 [4.Ba4+ c6 5.B×c6‡] d×c3 e.p. 4.Ba4+ R×a4 5.Rd7 [6.Rd8‡] 0-0 6.Rg7+ Kh8 7.Sg6‡

Grigory Popov
Olympic Tourney Istambul 2012
3rd HM
(= 10+13 )

11#

1.0-0! [2.Tf8‡] c1=D 2.D×c1 [3.Tf8‡] Fa7+ 3.d4 [4.Tf8‡] e×d3 e.p.+ 4.Rh1 [5.Tf8‡] 0-0-0 5.Df4 [6.D×c7‡] e5 6.d×e6 e.p. [7.D×c7‡] Td6 7.e7 [8.Df8+,e8=D+,e8=T+] T×c6 8.e8=D+ Rb7 9.D×c6+ R×c6 10.D×c7+ Rd5 11.Dd6‡

Many thanks for the #6 and #7 ichai-they are amazing masterpieces! Good idea to give a diagram to Popov's problem that I shared.

Here is the second known directmate Double Valladao that is also linked above.

Mikhail Kostylev, SuperProblem 2015, #8
(= 13+11 )

1. 0-0! c1=!/R/S 2. Qxc1 Bb6 + 3. d4 exd3+ 4 Kg2 f5 5. gxf6 g5 6. f7 + Bxf7 7. Rxf7 0-0-0 8. a8=Q/R#

EDIT-On chess.com. Arisktotle managed a decent key, so that miniature quest is now complete-https://www.chess.com/forum/view/more-puzzles/mate-in-5-a-black-triplet?page=2#last_comment

#4
(= 10+10 )

(7) Posted by Hauke Reddmann [Monday, Jul 20, 2020 10:37]; edited by Hauke Reddmann [20-07-20]

@all: Can you also make a little table which b/w combinations are